JEE MAIN - Physics (2023 - 1st February Morning Shift - No. 6)
The equivalent resistance between $$A$$ and $$B$$ of the network shown in figure;
_1st_February_Morning_Shift_en_6_1.png)
21 R
$$\frac{8}{3}$$ R
11$$\frac{2}{3}$$ R
14 R
Explication
_1st_February_Morning_Shift_en_6_2.png)
This is balanced Wheatstone bridge,
$$ R_{\mathrm{eq}}=\frac{4 R \times 8 R}{12 R}=\left(\frac{8 R}{3}\right) $$